Question

Two equal side of an isolceles triangle are each 2cm more than thrice the third side if the perimeter of the triangle is 67cm find the length of it's side

Answer 1

let the equal sides be=x
and, the third side be=y
so, according to question, 3y+2=x
now, perimeter of triangle= sum of all sides.
=2x+y=67
=2(3y+2)+y=67
=6y+4+y=67
=4+7y=67
y=9,x=29

Answer 2

Given = one Egual side= 2+x
            perimeter = 67
find out = side of tringle
Formula = add all sides
solution = Perimeter = Side 1 + Side 2 + Side 3
             = 67=2*2+x+2*2+x+x
            = 67= 4+3x+4
            = 67 = 8+3x
           = 67-8=3x
          = 59/3=x
          =19.6=x
Hence side 1 = 19.6+2
                    =  21.6
           side 2 = 21.6
            side 3 = 19.6