Question

two equal sides of a triangle are each 4 cm less than three times the third side. fins the sides of the triangle if its perimeter is 55 cm.​

Answer 1

Answer:

let 3rd side=x

1st side =2nd side =3x-4

ATQ

x+3x-4+3x-4=55

7x=55+4+4

7x=63

x=9

1st side =3×9-4=23m

2nd side =23m

3rd side =9m

Step-by-step explanation:

Answer 2

Answer:

Measure of sides = 17cm, 17cm and 21cm

Step-by-step explanation:

Let the 3rd side be 'x'

Then other two sides will be x-4

Now,

Perimeter of triangle = sum of all 3 sides.

thus, 55 = x + x-4 + x-4

ie, 55 = 3x-8

ie, 55+8 = 3x

ie, 63 = 3x

ie, 63/3 = x

ie, x = 21cm

thus, measure of third side = 21cm

and, measure of other two sides (x-4) = 21-4 = 17cm