two equal sides of a triangle are each 5 m less than twice the third side. if the perimeter of triangle is 55 M ,find the length of its sides.
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Let the first side and second side be x
And the third side be y
According to question,
2y-5=x
So, y = (x+5)/2
Perimeter of triangle = 55 m
x+x+y = 55
2x + (x+5)/2 = 55
(4x + x + 5)/2 = 55. {LCM}
5x + 5 = 110
5x = 105
x = 21 m
y = 26/2 = 13 m
WO lengths of sides of triangle are 21 m,21 m and 13 m
And the third side be y
According to question,
2y-5=x
So, y = (x+5)/2
Perimeter of triangle = 55 m
x+x+y = 55
2x + (x+5)/2 = 55
(4x + x + 5)/2 = 55. {LCM}
5x + 5 = 110
5x = 105
x = 21 m
y = 26/2 = 13 m
WO lengths of sides of triangle are 21 m,21 m and 13 m
khushi10630:
thanks
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4
This is the your answer x=20
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