Question

two equal sides of a triangle are each 5 meters less than twice the third side.the perimeter of the triangle is 55 meters. find the length the length of its sides ​

Answer 1

Step-by-step explanation:

Two sides of a triangle a/q

let it be x

2x-16 and 2x-16 and the third side is x

A/Q

2x-16+2x-16+x = 15

5x -32=15

5x=15+32

5x=47

x=47 by 5

the third side is 47 by 5 m

first and second side is 69 by 5 metres

This is your answer

FOLLOW ME

Answer 2

SOLUTION

let the third side of ∆ be x m.

let the third side of ∆ be x m.Then, Each equal side of ∆= (2x-5)m.

Given, perimeter of ∆= 55m

Perimeter of ∆= Sum of all sides of the∆

=)x+2x-5+2x-5= 55

=) 5x-10= 55

=) 5x= 55+10

=) 5x= 65

=) x=65/5

=)x= 13

Hence, the dimensions of the ∆= 13m

1st side= x= 13m

2nd side= 2x-5= 2×13-5

=) 26-5

=) 21m

Similarly, as 3rd side = 21m

hope it helps ☺️