two equal sides of a triangle are each 5 meters less than twice the third side.if the perimeter of the triangle is 55 meters,find the length of its sides
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let the 3 rd side be y
1 st and 2nd sides are =2y-5
(2y-5)+(2y-5)+y=55
5y=55
y=11
1 st and 2nd sides are =2y-5
(2y-5)+(2y-5)+y=55
5y=55
y=11
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