Question

two equal sides of an isoscles triangles are each 2 cm more than thrice the third side. If the perimeter of triangle is 67 cm find the lengths of its sides​

Answer 1

Let each side be X

one equal side = 3x +2

(3x + 2) x 2 + x = 67

7x + 4 = 67

7x = 67 - 4 = 63

x = 63 / 7 = 9

equal side = 3 x 9 + 2 = 27 + 2 = 29

third side = 9