Question

two equal sums of money were lent at s.i 11%p.a for 3½ years and 4½ years respectively. if the differences in interests for two perioeds was rs412.50 find each sum




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Answer 1

Answer:

Solution:-

Let each sum be x.

Given that rate of interest is 11%

Now according to the question-

100×2

x×11×9

−

100×2

x×11×7

=412.5

99x−77x=412.5×200

⇒22x=82500

⇒x=

22

82500

=3750

Hence the value of each sum is Rs.3750.