two equal vectors are along adjacent sides of a parallelogram and one of the diagonals root 3 times of the other then angle between vectors is
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angle between vectors is π/3.
It has given that two equal vectors are along adjacent sides of a parallelogram and one of the diagonals √3 times of the other.
we have to find the angle between vectors.
let two vectors v and w are sides of parallelogram as shown in figure.
so two diagonals are v - w and v + w
now, |v + w| = √3|v - w|
squaring both sides we get,
⇒(|v + w|)² = 3(|v - w|)²
⇒v² + w² + 2vwcosθ = 3(v² + w² - 2vwcosθ)
⇒v² + w² + 2vwcosθ = 3v² + 3w² - 6vwcosθ
⇒8vwcosθ = 2v² + 2w²
here a/c to question, v = w
so, 8v² cosθ = 2v² + 2v² = 4v²
⇒cosθ = 1/2 = cosπ/3
⇒θ = π/3
therefore, angle between vectors is π/3.
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