Two equal vectors are along adjacent sides of a parallelogram and one of the diagonals is√3 times the other. the angle between the vectors is.
a) π/3 b) π/6 c) 2π/3 d)π/4
Answers
Answer:
Given:
Two vectors a and b are along the adjacent sides of a parallelogram.
║a║=║b║
The length of one of the diagonal is √3 times the length of the other diagonal.
To find:
The angle between the two vectors a and b.
Solution:
Let the angle between the two vectors a and be α
The two diagonal vectors of the parallelogram can be given by (a+b) and (a-b).
║a+b║² = ║a║²+║b║²+2║a║║b║cosα = 2║a║²(1+cosα)
║a-b║² = ║a║²+║b║²-2║a║║b║cosα = 2║a║²(1-cosα)
It is given that, ║a+b║ = √3 ║a-b║
⇒║a+b║² = 3║a-b║²
⇒2║a║²(1+cosα) = 6║a║²(1-cosα)
⇒1 + cosα = 3 - 3cosα
⇒4cosα = 2
⇒cosα = 1/2
⇒α = π/3
Answer:
The angle between the two vectors a = π/3