Physics, asked by pragati3668, 11 months ago

two equipotential surfaces have electric field intensity 200 Newton per coulomb between them an hour potential difference of 20 V they are separated by a distance of​

Answers

Answered by samsonchristopher
1

Answer:

i =  \frac{q}{v}

Explanation:

200 =   \frac{?}{v}

200 =  \frac{q}{20}

200 \times 20 = q

q = 4000

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