Physics, asked by kirtigunjal7395, 8 months ago

Two exactly similar wire of steel and copper are stretched by equal force. If the difference in their elongations is 0.5 cm, the elongation (l) of each wire is Y_(s)("steel") =2.0xx10^(11) N//m^(2) Y_(c)("copper")=1.2xx10^(11)N//m^(2)

Answers

Answered by raytonbae
0

Answer:

their elongations is 0.5 cm, the elongation (l) of each wire is Y_(s)("steel") =2.0xx10^(11) N//m^(2) Y_(c)("copper")=1.2xx10^(11)N//m^(2)

Explanation:

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