Two exactly similar wires of steel and copper are stretched by equal force.If total elongation is 2 cm
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YS=Y --> steel 20×10^10 N/M²
YS=Y --> copper is 12×10^10 N/M²
ΔLs+ΔLc=1 --->eq1
YS= FL/ A ΔLs
YC=FL/ A ΔLC
YS/YC=[FL/ A ΔLs] /[FL/ A ΔLC]
YS/YC=ΔLc/ΔLs
ΔLC/ΔLS=YS/YC =20x10^10/12x10^10= 5/3
& ΔLS+ΔLC=1
ΔLS[1+ΔLc/ΔLs]=1
ΔLS[1+5/3]=1
ΔLS=[8/3]=1
ΔLS=3/8=0.375 cm
Substitute ΔLs in eq (1), we will get the value of ΔLC,,
ΔLC=0.625cm
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