Two exterior angles of a triangle equal 100° and 150°. Find all the interior angles.
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let exterior angle of A is 100 then angle CAB = 80
and exterior angle of B is 150 then angle ABC is 30( linear pair )
angle CAB+ angle ABC + angle ACB =180( angle sum property of triangle)
80+30+angle ACB = 180
angle ACB = 180-110= 70°
and exterior angle of B is 150 then angle ABC is 30( linear pair )
angle CAB+ angle ABC + angle ACB =180( angle sum property of triangle)
80+30+angle ACB = 180
angle ACB = 180-110= 70°
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