Math, asked by AdItYa302007, 8 months ago

Two faces each of a cube of side 6 cm have been painted blue, red and yellow. If it is cut
into cubes of side 1 cm each, then how many small cubes will have ONLY ONE side painted
either blue or red?​

Answers

Answered by Tharunpraveen
0

answer:64

Step-by-step explanation:

formula for no. of 1 side pained cubes=6(n-2)^2

here 6 represent no.of sides

here we should consider either red or blue which are on 4 surfaces

no. of 1 side painted cubes with these colors=4(n-2) ^2

4(6-2)^2

=4^3

=64

I hope you understood if not please comment

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Answered by amitnrw
0

Given : Two faces each of a cube of side 6 cm have been painted blue, red and yellow.  it is cut into cubes of side 1 cm each

To find : how many small cubes will have ONLY ONE side painted either blue or red?

Solution:

Number of cubes  = 6 * 6 * 6  = 216

No Face colored cubes = 4 * 4 * 4    = 64 cubes

only one face colored cubes  =  6 * 4 *  4  =  96 cubes  

two face colored cubes = 48

3 faces colored cubes   = 8

Only one side red cubes  =   2 * 4 * 4 =  32 cubes

Only one side blue cubes =   2 * 4 * 4 =  32 cubes

Only one side yellow cubes =   2 * 4 * 4 =  32 cubes

Either Blue or Red = 32 + 32 = 64 cubes  

64 small cubes have only one side painted either blue or red

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