Question

two fair coins tossed simultaneously. find the probability of getting no head ​

Answer 1

Answer:

Step-by-step explanation:

If we say that the coin is fair. Then getting a head or a tail have equal probabilities. So, P(H)=P(T)=1/2

Now, P(at most 1 head)=P(getting 0 heads or 1 head) = P(0 heads) + P(1 head) = P(T)*P(T)+P(H)*P(T)+P(T)*P(H)= 3/4

Or

When tossing two coins simultaneously, following are the possible outcomes- HH,TT,HT,TH. Out of which 3 are favourable in our case (TT,HT,TH).

Hence, required probability = 3/4

Answer 2

Sample Space n(s) = (H,H),(H,T),(T,T),(T,H)
n(s) = 4
let 'A' be the event of getting no head
A = (T,T)
n(A) = 1
p(A) = 1/4
Probability of getting no head p(A) = 1/4