Question

Two fair dice are rolled. What is the probability of the sum of the numbers on the top faces being a Mersenne prime?
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Answer 1

Answer:

Step-by-step explanation:

The total number of possible outcomes in this case is 36—

{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Out of the listed possibilities, the favorable outcomes are—

{(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)}

Hence, the number of favorable outcomes is 15.

Therefore, the required probability is 15/36 = 5/12.

Answer 2

Answer:

1/6

Step-by-step explanation:

Because the probability of getting mersenne prime is only one time