Math, asked by kumarr73092, 11 months ago

two fields in the shape of parallelogram and Rhombus are equal in area the diagonal of rhombus are 110 and 44 respectively if one of the sides of the parallelogram is 88 metre find its altitude​

Answers

Answered by aachhu007
6

Answer:

Hi,

As we know that the area of Rhombus is 1/2× diagonal1 × diagonal2

then

the area of Rhombus will be

1/2×120×44 = 260 sq m

we know that area of parallelogram is equal to area of Rhombus then

260 =66×its altitude which is equal to

260/66

:)

Step-by-step explanation:

Answered by pallavisagoi
6

Step-by-step explanation:

area of parallelogram = area of rhombus

diagonal of rhombus = 110m and 44m respectively

area of rhombus = 1÷2×55×44 =2420

area of parallelogram=2420

one of the sides (base)=88 m

let the altitude=X

Area of parallelogram=base ×height

2420 = 88 ×X

X=2420÷88 =27.5

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