Two fields one square and the other rectangular have the same perimeter the squares of one side 6 CM while the breadth of the rectangle is 40 m which field has the greater area and by how much
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Solution :
Theoretically Given : Two fields one square and the other rectangular have the same perimeter the squares of one side 6 CM while the breadth of the rectangle is 40 metres.
Given : Side of Square = 6 Centimeters
Breadth Of Rectangle = 40 metres
Now, According to the Question!
Perimeter of Square = Perimeter of Rectangle
✏ 4 × Side = 2(Length + Breadth)
✏ 4 × 60 = 2(Length + 40)
✏ 240 = 2l + 80
✏ 240 - 80 = 2l
✏ 160 = 2l
✏ Length = 80 Centimetres
Now, According to the Question!
Area of Square = (Side)²
✏ Area of Square = (60)²
✏ Area of Square = 3600 cm²
Area Of Rectangle = Length × Breadth
Area of Rectangle = 80 × 40
Area of Rectangle = 3200 cm²
Hence, Area of Square is Greater area by 400 cm² .
Theoretically Given : Two fields one square and the other rectangular have the same perimeter the squares of one side 6 CM while the breadth of the rectangle is 40 metres.
Given : Side of Square = 6 Centimeters
Breadth Of Rectangle = 40 metres
Now, According to the Question!
Perimeter of Square = Perimeter of Rectangle
✏ 4 × Side = 2(Length + Breadth)
✏ 4 × 60 = 2(Length + 40)
✏ 240 = 2l + 80
✏ 240 - 80 = 2l
✏ 160 = 2l
✏ Length = 80 Centimetres
Now, According to the Question!
Area of Square = (Side)²
✏ Area of Square = (60)²
✏ Area of Square = 3600 cm²
Area Of Rectangle = Length × Breadth
Area of Rectangle = 80 × 40
Area of Rectangle = 3200 cm²
Hence, Area of Square is Greater area by 400 cm² .
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