Question

Two fifth of A's money is equal to B's and seven -ninths of B's is equal to C's in all they
have 770. What have they each ?​

Answer 1

Step-by-step explanation:

answer:

x=450(he's money)

Answer 2

A,B, and C have Rs. 450, Rs. 180, and Rs. 140 respectively.

Given:

• (2/5)th of A's money is equal to B's and,
• (7/9)th of B's is equal to C's.
• In all they have 770.

To find:

• What have they each ?

Solution:

Step 1:

Let A has x rupees.

So,

B's money = (2/5)th of A's money

B's money $\bf = \frac{2x}{5}$

C's money = (7/9)th of B's money

C's money$= \frac{2x}{5} \times \frac{7}{9}$

or

C's money$\bf= \frac{14x}{45}$

Step 2:

Sum of all money is 770.

So,

$x + \frac{2x}{5} + \frac{14x}{45} = 770$

take LCM and solve.

$\frac{45x + 18x + 14x}{45} = 770$

or

$77x = 770 \times 45$

or

$x = 10 \times 45$

or

$\bf x = 450$

Step 3:

Find out money of each share.

As A's money is Rs. 450.

B's money $= \frac{2}{5} \times 450$

or

B's money is Rs 180.

C's money is $= \frac{7}{9} \times 180$

C's money is Rs 140.

Thus,

A,B, and C have Rs. 450, Rs. 180, and Rs. 140 respectively.

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