Two fill pipes can fill a cistern in 36 and 45 minutes respectively and one empty pipe can empty
the full cistern in 30 minutes. If the empty pipe is opened 7 minutes after both fill pipes are opened,
find when the cistern is full?
Answers
Answered by
1
Step-by-step explanation:
Part filled in 7 min =7×(
36
1
+
45
1
)=
20
7
Remaining part =1−
20
7
=
20
13
Net part filled in one minute when A, B and C are opened =
36
1
+
45
1
−
30
1
=
60
1
20
13
part is filled in 60×
20
13
=39 mins
Total time taken to fill the tank =(39+7)=46 min
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