Question

TWO FINITE SETS HAVE N AND M ELEMENTS. THE NUMBER OF ELEMENTS IN THE POWER SET OF FIRST SET IS 48 MORE THAN THE TOTAL NUMBER OF ELEMENTS IN POWER SET OF THE SECOND SET. THEN THE VALUES OF M AND N ARE

Answer 1

Answer:

m = 6, n = 4

Step-by-step explanation:

This question is totally based on power set concept.

Given, there are two finite sets having m and n elements.

Let Set1 has m elements and Set2 has n elements. 

Now, Power set of Set1 is

P(Set1) = 2^m 

and Power set of Set2 is

P(Set2) = 2^n

According to question,

     2^m - 2^n = 48

=> 2^m - 2^n = 64 - 16

=> 2^m - 2^n = 26 - 24

=> 2^m =  26 and 2^n = 24

=> m = 6, n = 4

Answer 2

Answer:

6 & 4

Step-by-step explanation:

the first  set has 2^6 elements         = 64 elements

the second set has 2^4 elements    = 16 elements

there fore  M AND N ARE 6 & 4