Question

two force of 60N and 40N are inclined to each other at an angle of 60°. find the magnitude and direction of their resultant .​

Answer 1

Answer:

R² = P² + Q² + 2 P Q cos Ф= 30² + 40² + 2x 30x 40 xcos 60= 900 + 1600 + 2400 * 1/2 = 3700

So, R = 10 √37 Newtons

Angle of the resultant force with 30 N force is

tan α = Q sin Ф / (P + Q cos Ф)

= 40 (√3 / 2)/ (30+(40*1/2)) = 2√3 / 5

α = tan-1 (2√3/5) = 34.7 degrees