Question

Two forces(10iˆ+14jˆ)N and (6iˆ+10jˆ)N act upon a body of mass 8 kg. Then the acceleration of the body is​

Answer 1

Answer:

Total force in X - direction = (10i+6i)=16i

total force in y-direction = (14j+10j)=24j

F resultant = √(Fi +Fj + 2F1F2 cosø)

since, Ø between i and j = 90°

F resultant = √[(16)² +(24)² +cos 90°]

F resultant = 28.8N

now,net acceleration = F/M = 28.8/8 =3.6m/s²

acceleration in x - direction = 16/8 = 2m/s²

acceleration in y-direction = 24/8= 3m/s²