Question

two forces 5N and 12N have their resultant magnitude 13N. what is the angle between the vectors?

Answer 1

We know,

|R|=
$\sqrt{ {f1}^{2} + {f2}^{2} + f1 \times f2 \times \cos( \alpha ) }$
therefore.

13=
$\sqrt{ {5}^{2} + {12}^{2} + 5 \times 12 \times \cos( \alpha ) ) }$
169= 169+ 60cos(alpha)

60cos(alpha)=0

Cos(Alpha)=0

alpha=90°

Therefore the angle between then is 90°


Hope this helps


Mark brainliest if it helps.

Answer 2

here is your answer.