Question

Two forces 6n and 8n are acting on a particle perpendicularly. Find the resultant force

Answer 1

√(6)^+(8)^

√36+64

√100

=10N

resultant force=10N

Answer 2

Given :

Two forces are given :

$F_1=6\ N$ and $F_2=8\ N$ .

Also , both the forces are perpendicular to each other .

Therefore , $\theta=90^o$ .

To Find :

The resultant force .

Solution :

We , know resultant force is given by :

$F_r=\sqrt{F_1^2+F_2^2+2F_1F_2cos\ \theta}$

We know , $cos\ 90^o=0$

Therefore , $F_r=\sqrt{F_1^2+F_2^2}$

Putting value of $F_1$ and $F_2$ in above equation .

We get :

$F_r=\sqrt{6^2+8^2}\\\\F_r=10\ N$

Therefore , the resultant force is 10 N .

Learn More :

Resultant Force

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