Question

two forces each of 5N are acting on an object but perpendicular to each other.what is the resultant force of the object​

Answer 1

Given :

Two forces each of 5N are acting on an object but perpendicular to each other.

To find :

The resultant force of the object.

Solution :

We know that,

If two vectors A and B of magnitudes A and B are acting at an angle θ, then the magnitude of their resultant (R) using parallelogram method of vector addition is

$\bf R = \sqrt{A^2 + B^2 + 2ABcos \theta}$

Where θ represents the angle between the two vectors.

As the two vectors are perpendicular to each other, θ = 90°.

$\dashrightarrow \sf R = \sqrt{A^2 + B^2 + 2ABcos \theta}$

$\dashrightarrow \sf R = \sqrt{5^2 + 5^2 + 2(5)(5)(0)}$

$\dashrightarrow \sf R = \sqrt{25 + 25 +0}$

$\dashrightarrow \sf R = \sqrt{50}$

$\dashrightarrow \sf R = 25\sqrt{2} \: N$

Thus, the resultant force of the object is 25√2 N.

Answer 2

Bonjour ⚘⚘

$Given :-$

• Two forces each of 5N are acting on an object but perpendicular to each other

$To find :-$

• Resultant force of the object.

$Solution :-$

As we know that,

$\boxed{ R = \sqrt{A^2 + B^2 + 2ABcos \theta}}$

Substitute the value,

$:\implies\:\: R = \sqrt{A^2 + B^2 + 2ABcos \theta}$

$:\implies\:\: R = \sqrt{5^2 + 5^2 + 2(5)(5)(0)}$

$:\implies\:\: R = \sqrt{25 + 25 +0}$

$:\implies\:\: R = \sqrt{50}$

$:\implies\:\: R = 25\sqrt{2} \: N$

• Resultant force of the object is $25\sqrt{2} \: N$