Two forces F1 and F2 are acting on an object F1=30N,F2=20N (i) What is the net force acting in the object ?(ii) What is the direction of the net force acting on the object ?(iii) If the mass of body is 10 kg what will be the acceleration produced in it ?
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Answered by
106
CASE 1] :-. If F1 and F2 are in same direction (say right)
(i) Net force=F1+F2 =50N
(ii) Direction of net force is in the same direction as of F1 or F2.
(iii) Since, F=m*a (a:- acceleration, m:- mass of object, F :- net force)
50=10a
acceleration= 5m/s^2 in the direction of net force.
CASE 2] :- If F1 and F2 are in opposite directions.
(i) net force is difference in the magnitude of the forces = 10N
(ii) The direction of the net force is always in the direction of the force with greater magnitude. So, the direction of the force is in the direction of the F1 .
(iii) F=m*a
10=10a
so, acceleration=1m/s^2 in the direction of net force, that is , in the direction of F1.
(i) Net force=F1+F2 =50N
(ii) Direction of net force is in the same direction as of F1 or F2.
(iii) Since, F=m*a (a:- acceleration, m:- mass of object, F :- net force)
50=10a
acceleration= 5m/s^2 in the direction of net force.
CASE 2] :- If F1 and F2 are in opposite directions.
(i) net force is difference in the magnitude of the forces = 10N
(ii) The direction of the net force is always in the direction of the force with greater magnitude. So, the direction of the force is in the direction of the F1 .
(iii) F=m*a
10=10a
so, acceleration=1m/s^2 in the direction of net force, that is , in the direction of F1.
Answered by
51
I. Net force = 30N - 20N = 10N
ll. Net force acts along the direction of F2
lll. F = ma
a = 10/10 = 1m/s²
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