Question

Two forces of in and PN actat
at a point so that the magnitude
of resultant is in and it is
peopendicated to in the value of
pin neatons and the angle between
the 1Nand pN
are,

Answer 1

Answer:

Given:

2 force of 1 N and P N are acting on a point such that magnitude of resultant is 1N . The resultant is at an angle of 90° to 1N vector.

To find:

• Value of P N
• Value if Angle between 1N and P N

Calculation:

Please refer to the attached photo to understand better .

Magnitude of P can be found out easily by using Pythagoras Theorem.

$\boxed{ \bold{P = \sqrt{ {1}^{2} + {1}^{2} } = \sqrt{2} }}$

So magnitude of P = √2 N

Now considering ∆ACD , we can say that

$\cos( \theta) = \dfrac{base}{hypotenuse}$

$= > \cos( \theta) = \dfrac{1}{ \sqrt{2} }$

$= > \theta = 45 \degree$

So total angle between 1 N vector and P N vector will be :

$\boxed{ \bold{ \angle(DAB) = (90 + 45) = 135 \degree}}$