Question

Two forces of magnitude 40 N and 55 N act on object in the different direction. What is the magnitude of the net force?​

Answer 1

Given :

• Magnitude of two forces acting on an object in two different directions are 40 N and 55 N.

To find :

• The magnitude of net force on the object

Solution :

Net force is calculated by adding all the forces acting on the body.

We are given that these two forces are acting in opposite to each other . Hence , in this case the difference between the larger force and smaller force gives the net force acting on the object.

Let the two force be F₁ and F₂ then ,

• F₁ = 40 N

• F₂ = 55N

$\\ : \implies \bf \: F_{net} = \: F_{2} - F_1 \\ \\ \\ : \implies \bf \: F_{net} = 55 \: N - 40 \: N \\ \\ \\ : \implies \boxed{{\bf{F_{net} = 15 \: N}}}$

Hence , The net force on the given object is 15 N

Answer 2

Answer:

Given :

Magnitude of two forces acting on an object in two different directions are 40 N and 55 N.

To find :

The magnitude of net force on the object

Solution :

Net force is calculated by adding all the forces acting on the body.

We are given that these two forces are acting in opposite to each other . Hence , in this case the difference between the larger force and smaller force gives the net force acting on the object.

Let the two force be F₁ and F₂ then ,

F₁ = 40 N

F₂ = 55N

\begin{gathered} \\ : \implies \bf \: F_{net} = \: F_{2} - F_1 \\ \\ \\ : \implies \bf \: F_{net} = 55 \: N - 40 \: N \\ \\ \\ : \implies \boxed{{\bf{F_{net} = 15 \: N}}}\end{gathered}

:⟹F

net

=F

2

−F

1

:⟹F

net

=55N−40N

:⟹

F

net

=15N

Hence , The net force on the given object is 15 N