Two forces of magnitude 8.0 N and 6.0 N act on a 4.5 kg body.
What is the acceleration produced when these forces are acting in the same direction?What is the acceleration when these forces are opposite directed?
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Answer:
When forces are acting in the same direction the acceleration
a=(F_1+F_2)/m=(6.0+4.0)/3.2=3.125 m/s^2 .
When forces are opposite directed
a=(F_1-F_2)/m=(6.0-4.0)/3.2=0.625 m/s^2 .
Answers:
(1) 3.125 m/s^2 ;
(2) 0.625 m/s^2 .
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