Factorise: 4a2 - 4ab + 2bc - c2
Answers
Answered by
3
Answer:
4a
2
+b
2
+c
2
−4ab+2bc−4ca
=(2a)
2
+(−b)
2
+(−c)
2
+2(2a)(−b)+2(−b)(−c)+2(2a)(−c)
We know that x
2
+y
2
+z
2
+2xy+2yz+2xz=(x+y+z)
2
Here, x=2a, y=−b and z=−c
So, 4a
2
+b
2
+c
2
−4ab+2bc−4ca
=(2a−b−c)
2
=(2a−b−c)(2a−b−c)
Answered by
0
Step-by-step explanation:
4a²- 4ab + 2bc - c²
=4a(a-b) +2c(b-c)
=(4a+2c)(a-b) (b-c)
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