Question

Factorise: 4a2 - 4ab + 2bc - c2​

Answer 1

Answer:

4a

2

+b

2

+c

2

−4ab+2bc−4ca

=(2a)

2

+(−b)

2

+(−c)

2

+2(2a)(−b)+2(−b)(−c)+2(2a)(−c)

We know that x

2

+y

2

+z

2

+2xy+2yz+2xz=(x+y+z)

2

Here, x=2a, y=−b and z=−c

So, 4a

2

+b

2

+c

2

−4ab+2bc−4ca

=(2a−b−c)

2

=(2a−b−c)(2a−b−c)

Answer 2

Step-by-step explanation:

4a²- 4ab + 2bc - c²

=4a(a-b) +2c(b-c)

=(4a+2c)(a-b) (b-c)