Two forces P ans Q acting at a point have a resultant R. If P is doubled , R is doubled and P is reversed in direction, even then R is doubled . Show that P:Q:R=√(6):√(2):√(5).
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Step-by-step explanation:
Two forces P ans Q acting at a point have a resultant R. If P is doubled , R is doubled and P is reversed in direction, even then R is doubled . Show that P:Q:R=√(6):√(2):√(5).
R² = P² + Q² + 2PQCosθ - eq 1
P doubled , R doubled
(2R)² = (2P)² + Q² + 2(2P)QCosθ
4R² = 4P² + Q² + 4PQCosθ b - eq 2
P is reversed , R is doubled
4R² = P² + Q² - 2PQCosθ - eq3
Eq 3 - Eq 1
3R² = -4PQCosθ
Putting in Eq 2
7R² = 4P² + Q² - Eq 4
Eq 3 + Eq1
5R² = 2P² + 2Q² - Eq 5
2 * Eq4 - Eq5
9R² = 6P²
3R² = 2P²
2*Eq5 - Eq 4 -
3R² = 3Q²
2P² = 3Q² = 3R²
=> P² : Q² : R² = 1/2 : 1/3 : 1/3
=> P² : Q² : R² = 6 : 4 : 4
=> P : Q : R = √6 : 2 : 2
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