two forces while acting on a particle in opposite direction have the resultant of 10N .if they act at right angles to each other. the resultant is 50 N find the two forces
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F1-F2=10
If acting perpendicular to each other
resulatant will be
F1^2+F2^2=2500
PUTTING. F1=F2+10
2F2^2+100+20F2=2500
F2^2+10F2-1200=0
F2=(-10+70)/2=30
F1=40
If acting perpendicular to each other
resulatant will be
F1^2+F2^2=2500
PUTTING. F1=F2+10
2F2^2+100+20F2=2500
F2^2+10F2-1200=0
F2=(-10+70)/2=30
F1=40
rajivnld2002p7qvsa:
hi mark brainliest
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