two forcesof 3N and 4N are acting at a same point such that angle between them is 60degree.Find the resultant force and angle made by resulting force with 4N
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Answer:
R = √ 3^2 + 4^2 + 2 (3) (4) cos 60°
= √ 9 + 16 + 24*1/2
= √9+ 16 + 12
= √37
Hence the resultant of two is √37.
And the angle made by resulting force with 4N is 30°
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