Question

Two friends Aisha and suchi have 40 and 61 numbers of same type of toys respectively which they have to distribute among two groups of children such that each one gets equal numbers of toys after distributing in such a manner Aisha and suchi are left with 5 toys each.Then find the total number of children who got the toys and the toys received by each child

Answer 1

Answer:

Total number of children = 13

Toys received by each child = 7

Step-by-step explanation:

Given that Aisha and Suchi are left with 5 toys each, hence

they distributed 35 toys and 56 toys each.

Let 'x' be the number of children in group in which Aisha distributed

Let 'y' be the number of children in group in which Suchi distributed

Let 'n' be the number of toys each child has got.

Thus, x*n=35 and y*n=56.

From the above equations it is clear that n is the g.c.d(35, 56) or divisor of g.c.d(35, 56).

But g.c.d = 7

Hence n = 7( n cannot be 1, because if n would have been 1 they would have distributed to some more children and henceforth they wouldn't been left with 5 each)

x = 5 and y = 8.

Total number of children who got the toys are x + y = 13,

Toys received by each child = 7.