Question

Two friends Ajay and Bunty can do a
work alone in 8 and 20 days respectively.
Find the amount of work done by them in
4 days.

▪︎4/13 th of total work
▪︎3/8 th of total work
▪︎17/23 th of total work
▪︎7/10 th of total work​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

The work done by Ajay  and Bunty = $\frac{7}{10}$ th of total work

Step-by-step explanation:

Given that

Ajay and Bunty can do a work in alone 8 and 20 days respectively

Let x be the total work

Ajay can do x work in 8 days

⇒ the work done by Ajay in 1 day  =  $\frac{x}{8}$

Bunty can do x work in 20 days

⇒ the work done in Bunty in 1 day = $\frac{x}{20}$    

the total work done by both Ajay and Bunty = $\frac{x}{8}$ + $\frac{x}{20}$  

                                                             = $\frac{5x+2x}{40}$  = $\frac{7x}{40}$  

the work done by Ajay and Bunty in 1 day = $\frac{7}{40}$ th of x  

the work done by Ajay and Bunty in 4 days =  4 × $\frac{7x}{40}$

                                                             =  $\frac{7x}{10}$  

the work done by Ajay and Bunty in 4 days = $\frac{7}{10}$ th of total work