Two friends are running on a track PQ. A and B start from P and after reaching at a point R. A turns back and meets
B at point S. After meeting at point 5, A and B continue towards Pand Q respectively A and B meet for the second time at point R Distance RQ 72 m and ratio of speed of A and B is 7:5. What is the length of the track ?
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Answer:
P_____60m___R__Xm____40m____Q
Total distance = 100 + X
Initially, A traveled 60m and B traveled (40 + X)m. Since time is same. So, Speed ∝ Distance.
SaSb=6040+X
Second time,
So, now total distance traveled by A = 100 + X + 40
Total distance traveled by B = 100 + X + 60 + X
These will be in the ratio of Speed of A and B
Thus,
SaSb=6040+X=100+X+40100+X+60+X
X = 40
Thus Total distance = 100 + X = 100 + 40 = 140 m
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