Question

Two friends are sitting on a merry-go-round at right angles to each other. The diameter of the merry-go-round is 14 m. After one and half rotation of the merry-go-round

Each of them will cover a distance of 66m.
Displacement of both will be 14m
The minimum distance between the two friends will be 7√2 m
All of these

Answer 1

Answer:

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Answer 2

Given:

Angles that the friends make with each other= 90 degrees

Diameter of the merry go round = 14m

To find:

The correct statement from the given options.

Solution:

The radius of the merry go round = 7m

Since they have covered one and a half rotation then:

The distance covered by them = 2πr + πr

= 3πr = 3 * 3.14 * 7 = 66m

Therefore, each of them will cover a distance of 66m.

Since, they come to the same place after one rotation so displacement will be 0 for the complete one rotation and for the next half rotation, displacement will be equal to the diameter of the merry go round i.e. 7m.

Therefore, the displacement of both is 14m.

Since they are at right angles the distance between them can be found by the Pythagoras theorem:

(7)² + (7)² = h²

h= 7√2

Therefore, the minimum distance between them is 7√2.

Therefore, all of the given options are correct.