Question

Two friends Ram and Shyam live 10 km apart from each other.They start from their homes at the same time on their cycles and ride towards each other.Ram travels at speed of 8 kmph and Shyam at the speed of 12 kmph. How far does Ram travel before they meet?

Answer 1

Answer:

4 km

Step-by-step explanation:

Here, let the time taken by Ram and Shyam to meet each other be X h

Now, Speed of Ram = 8 km/h

So, distance covered by him before meeting = Speed × Time = 8 km/h × X = 8x km

Again, the speed of Shyam = 12 km/h

So, distance covered by him before meeting= Speed × Time = 12 km/h × X = 12x km

So according to question,

$8x + 12x = 10 \\ = > 20x = 10 \\ = > x = \frac{10}{20} \\ = > x = \frac{1}{2}$

Now, distance covered by Ram

$= 8x \\ = 8 \times \frac{1}{2} \\ = 4 \: km$

So, Ram travelled 4 km.

OM NAMAH SHIVAYA

Debasish Biswal

Answer 2

Answer:

Ram travelled 4km before they meet each other.

Step-by-step explanation:

In reference to the below image:

Let's suppose, Ram and Shyam meet at a point that is x km away from Ram and as the total distance between them is 10 km , so they meet 10-x km away from Shyam.

Therefore, according to the formula:

$time = \frac{distance}{speed}$

Since both Ram and Shyam meet at the same time, hence we equalize the time taken by both to meet.

• $\frac{x}{8} = \frac{10-x}{12}$
• On solving, $12x = 80 - 8x$
• $x= 4 km.$

Hence, the distance Ram travelled before meeting is 4km and the distance Shyam travelled before meeting is 10-4 = 6km.

To read more about it refer: https://brainly.in/question/20072888