Question

Two girls,each of weight 400N climb up a rope through a height of 8 We name one of them the girl A and the other B . Girl A takes 20 s which B takes 50 s to accomplish this task. What is the power of each girl ? (PLEASE FAST)

Answer 1

we know that

Work Done (wd)= FS......

here, F=Weight=400N

S=Height=8 m

so, wd=400×8

          =3200 J

on the other hand....

B does the same work.... so wd=3200J

Now, P=W/T

For A, P=3200/20

            =160 watt

For B, P= 3200/50

            = 64 watt....

So, Power of Girl A is 160 Watt and that of B is 64 watt.....

Answer 2

In this question,

In case of Girl A,

Weight of girl (f) = 400 N
Height (s) = 8 m
Time(t) = 20 s

Now,

$= > power \: = \frac{f \times s}{t}$
$= > p \: \: = \frac{400 \times 8}{20} \: \: watt$

$= > p \: \: = (20 \times 8) \: \: watt$


$= > \: p \: \: = 160 \: \: watt$

Now,

In case of Girl B,

Weight of Girl (f) = 400 N
Height = 8 m
Time = 50 s

As we know that,

$= > power \: = \frac{f \times s}{t}$

$= > \: p \: \: = \frac{400 \times 8}{50} \: watt$

$= > \: p \: \: = (8 \times 8) \: watt$

$= > \: p \: \: = 64 \: \: watt$


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