two glass sphere of 10g and 20g are moving with a velocity of 3m/s and 2m/s they coloid after collision the velocity of a body changes to 2.5m/s find velocity of second
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According to momentum conservation,
m1u1+m2u2=m1v1+m2v2
0.010×3+0.020×2 = 0.010×2.5+0.020×v
0.0012 = 0.025+0.020v
0.0012-0.025=0.020v
-0.0238=0.020v
v=-0.0238÷0.020
v=-0.19m/s ans.
m1u1+m2u2=m1v1+m2v2
0.010×3+0.020×2 = 0.010×2.5+0.020×v
0.0012 = 0.025+0.020v
0.0012-0.025=0.020v
-0.0238=0.020v
v=-0.0238÷0.020
v=-0.19m/s ans.
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