Two h atoms in the ground state collide inelastically. the maximum amount by which their combined kinetic energy is reduced is
Answers
Answered by
3
Initial K.E of two hydrogen atoms in ground state =13.6ev=13.6ev
K.E of both H atoms before collision =2×13.6=27.2v2×13.6=27.2v
Since the collision is inelastic , linear momentum is conserved , but some K.E is lost .
If one H atom goes to first excited state and the other remain in the ground state , then their combined K.E after collision 13.622+13.61213.622+13.612=17.0ev=17.0ev
Reduction in combined K.E=27.2−17.0evK.E=27.2−17.0ev
=10.2ev
K.E of both H atoms before collision =2×13.6=27.2v2×13.6=27.2v
Since the collision is inelastic , linear momentum is conserved , but some K.E is lost .
If one H atom goes to first excited state and the other remain in the ground state , then their combined K.E after collision 13.622+13.61213.622+13.612=17.0ev=17.0ev
Reduction in combined K.E=27.2−17.0evK.E=27.2−17.0ev
=10.2ev
Similar questions