Physics, asked by ashwinij200610, 1 month ago

Two have a circular Lissajous figure, the phase difference (δ) and the amplitude (A

and B) of two superposing simple harmonic motions are respectively ______.

(a) δ = 0, A≠B

(b) δ = 0, A=B

(c) δ = π/2, A=B

(d) δ = π/2, A≠B​

Answers

Answered by brainly298
0

Answer:

Explanat ion:

Answered by 0000biswajitaich
0

Answer:

The correct answer is

c) del = pi / 2 , a = b.

Explanation:

This is because in a circular Lissajous figure, the two oscillations are in phase quadrature, meaning they have a phase difference of pi/2 radians. Additionally, the amplitudes of the two oscillations are equal. This results in a circular path of the point tracing out the Lissajous figure.

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