Two heaters rated at 1000w, 250v each are connected in series across a 250v, 50hz ac supply. The total power drawn from the supply will be:
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Answered by
90
Ans 500 W
P = V²/R
1000 = (250)²/R
R = 250*250/100 = 62.5 Ω
Heaters connected in Series
total resistance = 62.5+62.5 = 125 Ω
Power Drawn = (250)² / 125 = 500 W
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Answered by
4
Answer:
Explanation:
w=v^2/R
R1=R2=(250×250)/1000
=62.5
RTotal=62.5+62.5=125
I=250/RTotal
=250/125
=2A
Therefore total power=P1+P2
=I^2 ×R1+=I^2 ×R2
=4×62.5+4×62.5
=500watt
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