Question

two ice skaters inally at rest, push of each other.
if one sketer whose mass is 60 kg has a velocity or 2 m/s. What is the velocity of others who skater whose mass is 40 kg?​

Answer 1

Explanation:

Given,

Initial velocity, u

1

=0andu

2

=0

Mass,m

1

=60kgandm

2

=40kg

Final Velocity, v

1

=2ms

−1

From conservation of momentum

Final momentum = initial momentum

m

1

v

1

+m

2

v

2

=m

1

u

1

+m

2

u

2

60×2+40v

2

=0

v

2

=−3ms

−1

Hence, velocity of second skater is −3ms

−1