Question

Two identical balls ‘A’and 'B'are moving with
same velocity. If velocity of 'A' is reduced to
half and of 'B' to zero, then the rise in
temperatures of 'A' to that of 'B' is
1) 3:4 2) 4:1 3) 2:1 4)1:1​

Answer 1

Answer:

correct answer is option : 1 = 3: 4

Explanation:

For ball A:

mass= m

velocity=v

specific  heat =s

Energy dissipated for ball A= Initial k.e- final k.e

= $\frac{mv^{2} }{2}$  - $m(v/2)^{2} / 2$

=3/8 mv²

msΔTA= 3/8 mv²

For ball b:

Energy dissipated by ball b= 1/2 m v² - 0

=1/2 m v²

msΔTb=1/2 m v²

ΔTb= v²/2s

ΔTa/ Δtb= 3v²x2s/ 8s x v²

= 3/4

∴ΔTa:ΔTb= 3:4

Answer 2

Answer:

hope you UNDERSTOOD this answer to