Question

Two identical bulbs A and B are designed for same voltage.Their power rating are P(a) and P(b) respectively ,where P(a)>P(b).They are joined in series across a V voltage supply,then which bulb will draw more power.

Answer 1

Bulb A will draw more power because when joined in series pa will consume more power and rise in power of voltmeter

Answer 2

Answer:

Bulb A will receive more power.

Explanation:

Here it is given that A and B are designed for same voltage so, there voltage will be same.

=>Pa=V²/Ra

and also, Pb=V²/Rb

Given that,

Pb>Pa

=> V²/Rb>V²/Ra

Here, V² is equal, so they will be eliminated.

Therefore, 1/Rb>1/Ra

By cross multiplication, we get

Ra>Rb

Therefore bulb a will draw more power.