Question

Two identical cells, each of emf E, having negligible internal resistance, are connected in parallel with each other across an external resistance R. What is the current through this resistance? (1)

Answer 1

The cells are arranged as shown in the circuit diagram given below:As the internal resistance is negligible, so total resistance of the circuit = R Potential difference across the resistance = E
So, current through the resistance,E/R

Answer 2

Answer:

$I=\frac{E}{R}$

Explanation:

we will bw using Ohm's law, $R=\frac{V}{I}$ or $I=\frac{V}{R}$

as the cells are connected in parallel so the net emf will be the same = E

∵(emf = voltage)

∴ the current in the resistance is $I = \frac{E}{R}$