Two identical charges 5 micro c each are fixed at a distance of 8 cm and between them a charged partical of mass
Answers
Answered by
0
Answer:
As there is no external force on the system, so the net change is Mechanical energy is 0.
△U
system
=△K
charge
From the diagram,
U
i
=
5X10
−2
KX(5X10
−6
)(−10X10
−6
)
X2 =−20KX10
−10
J
U
f
=
4X10
−2
KX(5X10
−6
)(−10X10
−6
)
X2 =−25KX10
−10
J
△U
sys
=U
i
−U
f
=5KX10
−10
=4.5J
Now,
△U=△K=1/2mv
2
⟹4.5=0.5X9X10
−6
v
2
v=1000m/s
Similar questions