two identical charges are placed at two corners of an equilateral triangle solve it..
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Let 'q' be the magnitude of each charge
Let 'r' be the length of each side of the triangle ABC.
The potential energy of the system of two equal charges placed at a vertices A and B is V.
Hence the work done in bringing an identical charge q from infinity to the third vertex C = work done to overcome the force of repulsion of q placed at A placed at a distance r from it + work done to overcome the force of repulsion of q placed at B at the same distance r from it,
W=V+V=2V
hence the answer is2 volt.
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